UF MAD 4401 Homework
MAD 4401 Homework
Fall 2008
Note: Homework is due by 5:00 p.m. on the due date. Late homework is not accepted.
Important: The
numbers of homework problems listed are in the 8th edition of the
book.
Number | Due Date | Section Numbers | Problem Numbers |
1. | Sep 10 |
Section 1.2 Section 1.3 |
5f, 13c, 15c 6c, 7b |
2. | Sep 17 |
Section 2.1 Section 2.2 |
3c, 5b, 10b, 14 7, 11f |
3. | Sep 24 |
Section 2.3 |
6c, 8 and 10 with 6c, 29 c,d |
4. | Oct 1 |
Section 2.4 Section 3.1 |
6a, 9a 2a, 4 with 2a, 5a, 19d |
5. | Oct 15 |
Section 3.2 |
3b, 5b, 9a,b,12, 16, 17 |
6. | Oct 29 |
Section 3.3 Section 3.4 |
1c, 3c 2, 12, 13 |
7. | Nov 5 |
Section 4.1 Section 4.3 |
1b, 3b, 5a, 7a 1d, 5 and 9 with 1d, 18 |
8. | Nov. 12 |
Section 4.4 Section 4.7 |
8 a,b, 9, 11a 2 with 1h, 5 |
9. | Nov. 19 |
|
no hmwk this week |
10. | Dec. 1 |
Section 8.1 |
5 a, d, e |
11. | Dec. 8 |
no hmwk this week | |
12. | Apr. 21 |
Section 5.3 Section 5.4 |
5a, 6b, 7 with 5a 1c, 9 with 1c |
13. | |
Section 5.4 |
1c, 5, 9, 13 all with 1c |
Answers to Homework
Problems
Section
2.1: Problem 6: The Bisection Method gives p10=1.0068, accurate within
0.001.
Problem 12: n>= 12, p12=1.3787
Section 2.3: Problem 6c: p0=2
gives p4=2.370687; p0=4 gives p4=3.722113
Problem 8(with 6c): (i) p0=2, p1=3 gives p6=2.370687; p0=3, p1=4 gives
p7=3.722113
Section
2.4: Problem 4a: alpha=1, lambda=1, linear convergence.
Section 3.2: Problem 8: The
second forward-difference of P at 10 is 1140.
Section 3.3: Problem 2c: H3(-1/3)
= 0.1745185 (approximation), f(-1/3) = 0.17451852 (exact).
Section 3.4: Problem 2:
s(x)=x on [0,2].
Problem 8: a=4, b=4, c=-1, d=1/3.
Section 4.1: Problem
2b: x Actual Error Error
Bound
0.0
0.293
0.3
0.2 0.2694
0.2779
0.4 0.2602
0.2779
Section
4.3: Problem 12: c0=1/3, c1=4/3, c2=1/3
Section 4.4: Problem 4: a)
0.421582; b) 0.4227162; c) 0.4249845
Section 4.7: Problem 2h:
0.6427011
Section 5.2: Problem 4a:
t Actual error
1.2 0.0066879
1.5 0.0095942
1.7 0.0102229
2.0 0.0105806
Problem 6c: h<0.029
Section 5.4: Problem
2c: ti
wi
1.25 2.7767857
1.5 3.6042017
1.75 4.4736520
2.00 5.3790494
Section 6.1: Problem
2a: x1=1, x2=-0.98, x3= 2.9;
Problem 6: a) alpha=1, b) alpha=-1, c) x1=-1/(1-alpha), x2=1, x3=
1/(1-alpha)
Section 6.3: Problem
2b: 1,1,1
Section 6.4: Problem
6: alpha=6
Section 6.6: Problem
10: alpha>8/7
Internal Links
UF MAD 4401 Numerical Analysis
Internal Links
Parent Article: UF_MAD_4401_Numerical_Analysis